Dashboard/Block 1: Foundations/Week 1
Week 1Foundations

Permutations, Combinations & Binomial Theorem

This week introduces the fundamental counting principles that underpin combinatorics and discrete mathematics. We cover ordered and unordered selections with and without replacement, binomial coefficients, the Binomial Theorem, and Pascal's triangle. These tools are essential for counting arguments that appear throughout graph theory.

Learning Objectives

Distinguish between ordered and unordered selections with and without replacement
Compute binomial coefficients and prove key identities combinatorially
State and apply the Binomial Theorem
Construct and use Pascal's triangle

Key Concepts

Counting Principles

The foundation of combinatorics rests on two principles:

  • -Product Rule: If task A can be done in mm ways and task B in nn ways, then A followed by B can be done in mnm \cdot n ways
  • -Sum Rule: If task A can be done in mm ways OR task B in nn ways (mutually exclusive), then there are m+nm + n ways total

These extend to ordered selections: permutations count arrangements where order matters, while combinations count selections where order does not.

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    Permutations of nn objects: n!n!

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    P(n,k)=n(n1)(nk+1)P(n,k) = n \cdot (n-1) \cdot \ldots \cdot (n-k+1)

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    (nk)=(nnk)\binom{n}{k} = \binom{n}{n-k} (symmetry)

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    Selections with replacement: nkn^k ordered, (n+k1k)\binom{n+k-1}{k} unordered (stars and bars)

Binomial Coefficients & Identities

Binomial coefficients (nk)\binom{n}{k} count the number of ways to choose kk items from nn. They satisfy many useful identities:

  • -Pascal's Rule: (nk)=(n1k1)+(n1k)\binom{n}{k} = \binom{n-1}{k-1} + \binom{n-1}{k}
  • -Vandermonde's Identity: (m+nr)=k=0r(mk)(nrk)\binom{m+n}{r} = \sum_{k=0}^{r} \binom{m}{k}\binom{n}{r-k}
  • -Sum of row: k=0n(nk)=2n\sum_{k=0}^{n} \binom{n}{k} = 2^n
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    Pascal's triangle row nn gives the coefficients of (x+y)n(x+y)^n

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    Setting x=y=1x=y=1 gives 2n=(nk)2^n = \sum \binom{n}{k}

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    Setting x=1,y=1x=1, y=-1 gives 0=(1)k(nk)0 = \sum (-1)^k \binom{n}{k} (equal number of even/odd subsets)